Project Euler Problem 6: The sum of the squares of the first ten natural numbers is, 12 + 22 + … + 102 = 385. The square of the sum of the first ten natural numbers is, (1 + 2 + … + 10)2 = 552 = 3025. Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

Solution: The problem is quite straight forward. We have to to find two sums and then find the difference. Here is an Brute force approach for it. Enter the range as 100 in the prompt. And you are good to go.

**Java implementation of above is as follows:**

`import`

java.io.*;

`class`

DiffOfSquares`{`

` ``int`

range;

` ``long`

sumOfSq,sqOfSum;

` ``long`

diffOfSq;

` `

` ``void`

findDiff`(`

`)`

`{`

` ``int`

i=`1`

;

` ``for`

`(`

i = `1`

;i<=range;i++`)`

`{`

` sumOfSq += i*i;`

` sqOfSum += i;`

` ``}`

` sqOfSum *=sqOfSum;`

` `

` diffOfSq = sqOfSum - sumOfSq;`

` System.out.println``(`

`"The Sq of Sum is :"`

+sqOfSum`)`

;

` System.out.println``(`

`"The Sum of sq is :"`

+sumOfSq`)`

;

` System.out.println``(`

`"The Differnce is :"`

+diffOfSq`)`

;

` ``}`

` ``void`

setRange`(`

`)`

`{`

` System.out.println``(`

`"Enter the range :"`

`)`

;

` InputStreamReader isr = ``new`

InputStreamReader`(`

System.in`)`

;

` BufferedReader br = ``new`

BufferedReader`(`

isr`)`

;

` `

` ``try`

`{`

` String str = br.readLine``(`

`)`

;

` range = Integer.parseInt``(`

str`)`

;

` ``}`

` ``catch`

`(`

IOException e`)`

`{`

`}`

` `

` findDiff``(`

`)`

;

` ``}`

`}`

`class`

Test`6`

`{`

` ``public`

`static`

`void`

main`(`

String `[`

`]`

args`)`

`{`

` DiffOfSquares d = ``new`

DiffOfSquares`(`

`)`

;

` d.setRange``(`

`)`

;

` ``}`

`}`

Enjoy Coding !!!